How many gametes can be formed by AaBbCC individuals?

Complete answer: AABbcc will produce 2 types of gametes which are as follows- ABc, Abc. The number of gametes formed is set by the number of heterozygous alleles present within the given genotype.

What are the possible gametes for AaBbCc?

The plant having genotype AABbCC is heterozygous for only one character B. Number of “gametes = 2n”, where n is the heterozygosity.” Since n = 1 so 2 gametes will be formed. Those are ABC and AbC. So the two types of gametes will be ABC and AbC.

How many phenotypes are possible AaBbCc?

In the above cross$AaBbCc times AaBbCc$, there are three pairs of characters which are Aa, Bb, Cc. Therefore, the number of possible phenotypes are ${2^3} = 8$. Hence, the correct option is C. 8.

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How many types of gametes are formed by a plant having AaBbCc genotype in which A and B genes shows complete linkage?

In this case of genotype AABbCc, A gene will give only one type of gamete, B can give two types of gametes and c can give two types of gametes. Thus, totally four types of gametes will be produced.

How many allele combinations are in AaBbCc?

There are four possible combinations of gametes for the AaBb parent. Half of the gametes get a dominant A and a dominant B allele; the other half of the gametes get a recessive a and a recessive b allele. Both parents produce 25% each of AB, Ab, aB, and ab.

What skin color is AABbCc?

 Someone who is aabbcc would have very light skin color.

What is the proportion of genotype AABbCc in resulting generation by selfing a plant having the genotype AABbCc?


How many offsprings will be formed in mating between AABbCC * AABbCC?

Mating between the genotypes AAbbCCDd x AaBbCcdd produces 16 different types of offsprings. Types of gametes formed are determined by 2ⁿ where n stands for degree of heterozygosity.

How many types of phenotypes are produced from the selfing of a plant with genotype AABbCC?

AABbCC will produce two type of gametes ABC and AbC. Thus in F, generation three genotypes will be obtained. These are AABBCC, AABbCC and AAbbCC in the ratio of 1 : 2 : 1.

Which of the following individuals can produce 16 different gametes?

Question : Which one of the following individuals can produce 16 different gametes?

  • A. Aa Bb cc Dd.
  • B. Aa Bb cc DD Ee Ff.
  • C. Aa Bb Cc dd EE FF.
  • D. Aa Bb Cc DD Ee Ff.
  • Answer. B.
  • It is hexahybrid and, therefore, number f gametes are (2)6 but cc and DD are homozygous and hence number of gametes will be (2)6-2=(2)4=16.
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How many different types of gametes are formed from AaBbCcDdEe?

The number of different possible gametes produced by the diploid genotype (AaBbCcDdEe) is 2 x 2 x 2 x 2 x 2 = 32 (2 for each pair of heterozygous genes). 15.

How many gametes are in a Trihybrid cross?

27:9:9:9:3:3:3:1 ratio: As can be seen in the forked line diagram above, a trihybrid cross yields a phenotypic ratio of 27:9:9:9:3:3:3:1. This reflects the phenotypes generated by the 64 genotypic combinations resulting from 8 different male gametes fertilizing 8 different female gametes.

How many types of gametes are produced by the individual with genotype Aabbccdd and Aabbccdd?

One type by AABBCCDD & 16 type by individual Aa Bb Cc Dd (24 = 16).